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5v^2-35v-160=0
a = 5; b = -35; c = -160;
Δ = b2-4ac
Δ = -352-4·5·(-160)
Δ = 4425
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4425}=\sqrt{25*177}=\sqrt{25}*\sqrt{177}=5\sqrt{177}$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-5\sqrt{177}}{2*5}=\frac{35-5\sqrt{177}}{10} $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+5\sqrt{177}}{2*5}=\frac{35+5\sqrt{177}}{10} $
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